Use of potentiometer or rheostat to determine resistance – need clarification

Click For Summary
SUMMARY

The discussion focuses on the use of a potentiometer and a rheostat for measuring resistance in electrical circuits. A potentiometer can divide voltage to any value between zero and the voltage source, while a rheostat, functioning as a variable resistor, is used in series to create variable current. Both methods generate voltage and current pairs that can be plotted to calculate resistance using the formula V/I = R. The choice between the two methods depends on the resistor size and the need for voltage control, with the potentiometer generally preferred for its stability against thermal variance.

PREREQUISITES
  • Understanding of Ohm's Law (V/I = R)
  • Familiarity with potentiometers and rheostats
  • Basic knowledge of voltage and current measurement techniques
  • Experience with plotting graphs for data analysis
NEXT STEPS
  • Research the differences between potentiometers and rheostats in circuit applications
  • Learn about thermal effects in resistive components, specifically I2R losses
  • Explore advanced techniques for measuring low resistance values accurately
  • Investigate the use of data visualization tools for plotting V-I characteristics
USEFUL FOR

Electronics students, hobbyists, and engineers interested in circuit design and resistance measurement techniques.

elvinc
Messages
10
Reaction score
0
Hello

I understand

Homework Statement



1) a potentiometer can be used to divide a voltage to any value between zero and the voltage source. This can be used to place a variable voltage through a resistor

2) A rheostat (variable resistor) which is placed in series with the resistance to be measured can create a variable current through the resistor.

Now if voltage and current is measured in both setups as either the potentiometer or rheostat is changed both will generate pairs of values for voltage across and current through the resistor under test.

Homework Equations


V/I = R

The Attempt at a Solution


Plotting V against I for both sets of experiments would enable me to calculate the resistance as gradient of the plot. So which method (if one is to be preferred) should be used to determine the test resistance? Why?

Thanks,

Clive
 
Physics news on Phys.org
Welcome to PF.

Intuitively I would choose the potentiometer, because I could expect to want to control the voltage source across the test piece. A rheostat may have some thermal variance with different current loads (I2R), that I would expect a potentiometer would mitigate to some degree.

But in large part it depends on the size of the resistors you would be trying to measure. If they are very small values of ohms, things could be more challenging regardless of what method you would choose.

That's just me. Others may have better reasons than my intuition to choose one or the other, and if so, then by all means help the fellow out. It hasn't been addressed for half a day.
 

Similar threads

  • · Replies 59 ·
2
Replies
59
Views
14K
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
12K
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 32 ·
2
Replies
32
Views
9K