Use Thevenin’s and Norton’s theorems to find the current in RL for the

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SUMMARY

The discussion focuses on applying Thevenin’s and Norton’s theorems to determine the current through a load resistor (RL) in a given circuit. The user successfully calculated the Thevenin equivalent voltage (VTH = 33.793 - j5.517) and impedance (ZTH = 19.068 + j11.172), and subsequently derived the load current (I = 0.489 ∠ -18.401 degrees). The user also inquired about the Norton equivalent and confirmed that the Norton current (IN) can be calculated as IN = VTH/ZTH, facilitating the calculation of the load current (IL) using the relationship IL = IN(ZTH/(ZTH + RL)).

PREREQUISITES
  • Understanding of Thevenin’s theorem
  • Familiarity with Norton’s theorem
  • Complex number arithmetic
  • Knowledge of AC circuit analysis
NEXT STEPS
  • Study the derivation of Thevenin and Norton equivalents in AC circuits
  • Learn about converting complex numbers to polar form
  • Explore load resistor calculations in AC circuits
  • Investigate practical applications of Thevenin’s and Norton’s theorems in circuit design
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis will benefit from this discussion, particularly those looking to deepen their understanding of Thevenin’s and Norton’s theorems.

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Homework Statement


Use Thevenin’s and Norton’s theorems to find the current in RL for the circuit

TASK1_A.jpg


Homework Equations


The Attempt at a Solution


Thevenin equivalent
THEV.jpg


I have calculated VTH and ZTH
VTH=33.793-j5.517
ZTH=19.068+j11.172
Then I converted them in polar forms
Thefore I calculated the current through the load resistor I=VTH/ZTH+RL
I=0.489<-18.401

Homework Statement


My problem is Norton equivalent.Can it be represented like this:
nortas.jpg


and then IN=VTH/ZTH,once I find IN can easily calculate IL=IN(ZTH/ZTH+RL)
 
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shaltera said:

Homework Statement


Use Thevenin’s and Norton’s theorems to find the current in RL for the circuit

TASK1_A.jpg


Homework Equations





The Attempt at a Solution


Thevenin equivalent
THEV.jpg


I have calculated VTH and ZTH
VTH=33.793-j5.517
ZTH=19.068+j11.172
Those values look fine.

Then I converted them in polar forms
Thefore I calculated the current through the load resistor I=VTH/ZTH+RL
I=0.489<-18.401
The current magnitude looks good. Maybe a typo in the second decimal place of the angle?

Homework Statement


My problem is Norton equivalent.Can it be represented like this:
nortas.jpg


and then IN=VTH/ZTH,once I find IN can easily calculate IL=IN(ZTH/ZTH+RL)
Yes, that's correct.
 
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