Using pascal's triangle and standard form

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SUMMARY

The discussion focuses on calculating (z+w)5 where z = 4 + i and w = -2 + 2i using Pascal's Triangle and standard form. The correct approach involves first calculating z + w, resulting in 2 - i. Then, (2 - i)5 is evaluated using the coefficients from the 5th row of Pascal's Triangle, which are essential for expanding the binomial expression. The discussion emphasizes the importance of recognizing the relationship between binomial expansions and complex numbers.

PREREQUISITES
  • Understanding of complex numbers and their operations
  • Familiarity with binomial expansion and Pascal's Triangle
  • Knowledge of powers of complex numbers
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of complex numbers and their geometric interpretations
  • Learn how to apply Pascal's Triangle for binomial expansions
  • Explore the calculation of powers of complex numbers using De Moivre's Theorem
  • Investigate applications of binomial expansions in polynomial equations
USEFUL FOR

Students studying complex numbers, mathematics educators, and anyone interested in advanced algebraic techniques involving binomial expansions and complex number operations.

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Homework Statement



If z = 4 + i and w = -2 +2i, determine (z+w)5 using Pascal’s Triangle and standard form.

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The Attempt at a Solution

 
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?? (z+w)5= 5z+ 5w which has nothing to do with Pascal's triangle. Did you mean (z+ w)^i?

The first thing I would do is write z+ w= 4+i- 2+ 2i= 2- i.

so (z+ w)^5= (2- i)^5. Now, Pascal's triangle gives the coefficients for binomials of the form (a+ b)^n. In particular, the 5 th row of Pascal's triangle gives the coefficients for (a+ b)^5. Write that out, and remember that i^2= -1.
 

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