?? (z+w)5= 5z+ 5w which has nothing to do with Pascal's triangle. Did you mean (z+ w)^i?
The first thing I would do is write z+ w= 4+i- 2+ 2i= 2- i.
so (z+ w)^5= (2- i)^5. Now, Pascal's triangle gives the coefficients for binomials of the form (a+ b)^n. In particular, the 5 th row of Pascal's triangle gives the coefficients for (a+ b)^5. Write that out, and remember that i^2= -1.