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## Homework Statement

I am studying Gerry's <Introductory Quantum Optics>, in which there is an integral (Eq. 4.37)

$$\intop_{-infinity}^{+infinity}\frac{[sin(\triangle t/2)]^{2}}{\triangle^{2}}d\triangle=\frac{\pi}{2}t.$$

I don't know how to get the result of the right side.

## Homework Equations

I have no idea.

## The Attempt at a Solution

I tried like the following

$$\intop_{-infinity}^{+infinity}\frac{[sin(\triangle t/2)]^{2}}{\triangle^{2}}d\triangle=\intop_{-infinity}^{+infinity}\frac{1-cos(\triangle t)}{2\triangle^{2}}d\triangle$$

But don't know what to do next.