Using resistor and DC motor acting as generator as a brake

In summary, to calculate the resistance required for a resistor in series with a generator (DC motor in reverse) to achieve a certain torque, you need to consider the amount of work being done in running the generator circuit. This is a similar mechanism to that used in electric diesel locomotives for rheostatic braking. Additionally, it is important to ensure that the motor is suitable for use as a generator. Converting RPM to angular velocity and ensuring the torque is in the correct units is also necessary for accurate power calculations.
  • #1
Ry122
565
2
how would you calculate the resistance required for a resistor which is in series with a generator (DC motor in reverse) to achieve a certain torque from the generator?
Eg, there's a torque of 30kN acting on a 100kW generator while it moves at 50RPM.
The is the same mechanism as electric diesel locomotives use to brake that employ rheostatic braking.
 
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  • #2
You have to ask yourself how much work is being done to run the generator circuit.
 
  • #3
Ry122 said:
how would you calculate the resistance required for a resistor which is in series with a generator (DC motor in reverse) to achieve a certain torque from the generator?
Eg, there's a torque of 30kN acting on a 100kW generator while it moves at 50RPM.
The is the same mechanism as electric diesel locomotives use to brake that employ rheostatic braking.

If this is a real, practical problem then the motor would need to be a suitable one. Many motors will not work as generators, particularly not high power motors, with field windings.
Your suggested 100kW generator is quite a meaty piece of kit.

Note. If you want to calculate power (in Watts), as Simon B suggests, you will need to convert your RPM to angular velocity (and get your Torque in the right units, too - do you mean kNm?)
 

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