Using the analytic definition of a function

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SUMMARY

The discussion focuses on evaluating the derivative of the function f(x) = sqrt(1^2 + x^2) at the point x = 1/2 using the analytic definition of a derivative. The limit process is outlined, emphasizing the need to manipulate the expression by multiplying by the conjugate to simplify the limit calculation. The correct limit expression is presented as lim(h→0) [(sqrt(1 - (1/2 + h)^2) - sqrt(1 - (1/2)^2)) / h]. This approach clarifies the steps necessary to derive the function's behavior at the specified point.

PREREQUISITES
  • Understanding of calculus concepts, specifically limits and derivatives.
  • Familiarity with the analytic definition of a derivative.
  • Knowledge of algebraic manipulation techniques, including rationalizing expressions.
  • Basic proficiency in evaluating square root functions.
NEXT STEPS
  • Study the process of rationalizing expressions in calculus.
  • Learn about the formal definition of derivatives and its applications.
  • Explore advanced limit techniques, such as L'Hôpital's Rule.
  • Practice evaluating derivatives of various functions using the limit definition.
USEFUL FOR

Students studying calculus, particularly those working on derivatives and limits, as well as educators seeking to clarify the analytic definition of a function.

JacobHempel
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Homework Statement



The best way to represent this problem is with a snapshot of the problem.

Ha.jpg


Hopefully that works.

Homework Equations



f(x) = sqrt(1^2+x^2)

The Attempt at a Solution



f'(1/2) = lim(h>0) (1-h)/B = 1-0/B = 1/B ... B = -1/(Sqrt(3)
 
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What I don't get is letter b. I don't understand the process in which started from lim(h>0) ((f(1/2+h)-(f(1/2))/h all the way to lim(h>0)1-h/b ...
 
Nope. That's definitely not the best way to do (show) it. First start with:

[tex]\lim_{h\to 0} \frac{\sqrt{1-(1/2+h)^2}-\sqrt{1-(1/2)^2}}{h}[/tex]

Ok, don't even look at the printout. Now, in order to evaluate that limit (simply), we need some more h's on the bottom. We can do that by multiplying top and bottom by what, I forgot what it's called but:

[tex]\lim_{h\to 0} \frac{\sqrt{1-(1/2+h)^2}-\sqrt{1-(1/2)^2}}{h}\frac{\sqrt{1-(1/2+h)^2}+\sqrt{1-(1/2)^2}}{\sqrt{1-(1/2+h)^2}+\sqrt{1-(1/2)^2}}[/tex]

Now I bet you can do all that algebra, simplify it, and then take the limit as h goes to zero. Then figure out what that paper is asking you to do with the details.
 

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