Using the Weierstrass M-test to check for uniform convergence

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SUMMARY

The series \( f(x) = \sum_{n=0}^\infty{\frac{nx}{1+n^4 x^2}} \) converges uniformly on the interval \([1,\infty]\) by applying the Weierstrass M-test. The term \( \frac{nx}{1+n^4 x^2} \) is bounded above by \( \frac{1}{n^3} \), which is a convergent p-series. The series function equals zero for \( n=0 \), confirming that it does not affect convergence. Thus, the application of the Weierstrass M-test is validated, establishing uniform convergence definitively.

PREREQUISITES
  • Understanding of the Weierstrass M-test
  • Knowledge of uniform convergence
  • Familiarity with p-series convergence
  • Basic calculus involving series and limits
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  • Learn about p-series and their convergence criteria
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Mathematics students, educators, and researchers focusing on real analysis, particularly those studying series convergence and uniform convergence criteria.

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Homework Statement



\text{Show that the series }f(x) = \sum_{n=0}^\infty{\frac{nx}{1+n^4 x^2}}\text{ converges uniformly on }[1,\infty].

Homework Equations





The Attempt at a Solution



I think we should use the Weierstrass M-test, but I'm not sure if I'm applying it correctly:

For x \in [1,\infty) we have

\frac{nx}{1+n^4 x^2} \leq \frac{n}{n^4} = \frac{1}{n^3}

and \sum_{n=1}^\infty {\frac{1}{n^3}} is a convergent p-series.

Also, for n=0, we have the series function is equal to 0, so this will not affect the convergence of the series.

Therefore, by the Weierstrass M-test, the original series is uniformly convergent.

Have I got it right? Thanks in advance.
 
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Your estimate is right : nx/(1 + n^4* x^2) attains a maxima equal to 1/2n
(at x = 1/n^2) & decreases there onwards.
 

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