##v_{rms}## in the Kinetic Theory Of Gases

Click For Summary
SUMMARY

The discussion centers on the significance of root mean square velocity (##v_{rms}##) in the Kinetic Theory of Gases. The arithmetic mean of molecular velocities results in zero, which is unhelpful for understanding gas behavior. The ##v_{rms}## provides a meaningful average that correlates with kinetic energy, as it is derived from the square of the speeds of gas molecules. This method allows for the inference of average speeds from temperature measurements, making it essential for thermodynamic calculations.

PREREQUISITES
  • Understanding of Kinetic Theory of Gases
  • Familiarity with the concept of kinetic energy
  • Basic knowledge of statistical averages
  • Awareness of temperature measurement in gases
NEXT STEPS
  • Research the derivation of the root mean square velocity formula
  • Explore the relationship between kinetic energy and molecular speed
  • Study equipartition theorem in thermodynamics
  • Learn about statistical mechanics and its applications in gas behavior
USEFUL FOR

Students of physics, researchers in thermodynamics, and professionals in fields involving gas dynamics will benefit from this discussion.

Kaushik
Messages
282
Reaction score
17
In Kinetic theory of gases, what is the reason behind introducing a new kind of average known as root mean square velocity (##v_{rms}##)?

I read the following: The molecules in a container are in constant random motion. So when we add all the velocity vectors to find the average it cancels out and gives ##v_{av} = 0##. So to avoid this we square the velocities (to get rid of the sign) and then add them.

Is there any other reason? I read that there is another reason which is associated with equipartition (but it did not mention the reason). What could that reason be?
 
Physics news on Phys.org
Kaushik said:
Summary:: Why do we use ##v_{rms}##

a new kind of average
The arithmetic mean of velocities of all molecules would be zero (assuming the mass of gas is not moving). That would be of little use. RMS is only zero when all molecules are stationary and, as a measure of Energy, for instance, it is useful. The formula for RMS is the same as for statistical Standard Deviation (which again avoids the problem of the mean of a distribution about zero can be zero).
 
  • Like
Likes   Reactions: Kaushik
Kaushik said:
I read that there is another reason which is associated with equipartition (but it did not mention the reason). What could that reason be?

At a given temperature, on average, each molecule has the same amount of kinetic energy. When you average the kinetic energies you are averaging the squares of the speeds of each molecule because the kinetic energy is proportional to the square of the speed. If you then take the square root of that average you get a number that is roughly equivalent to the speed.

The reason we do it this way is because we can measure the temperature of the gas and from that we can infer the average of the squares of the speeds. We have no way of measuring or inferring the speed.
 
  • Like
Likes   Reactions: Kaushik

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 27 ·
Replies
27
Views
15K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K