Vacuum travel formula creation

  • Thread starter yrh
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  • #1
yrh
2
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Say we have a maglev train travelling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the travelling time of such a train as a function of the distance?
 

Answers and Replies

  • #2
pseudophonist
48
0
[tex]t=\sqrt{\frac{4s}{g}}[/tex]
where t is the time, s is the distance and g is the accelleration.
Calculated using the fact that distance travelled is the area underneath a velocity-time graph.
 
  • #3
yrh
2
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Thank you.

What acceleration value g should I use? I'm looking for an acceleration/deceleration that is hardly noticeable for the passengers, making the journey comfortable.
 
  • #4
torquil
649
2
With an acceleration of 0.5m/s^2 you can cross the USA in 1.5h in a straight line, which is pretty good...

The chairs could turn 180 degrees when the train is going to decelerate. The top speed would be 2.7km/s.

The usual problem with trains is that they start and stop at all the intermediate stations...
 
  • #5
uros
17
0
Say we have a maglev train travelling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the travelling time of such a train as a function of the distance?

At the distance x the train is accelerated until x/2 so the time is expressed as:
x/2=gt²/2
t=√x/g
 

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