Value of Vout in PMOS Inverter?

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jean28
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Hey guys. I am simply trying to derive the equation for Vout in a PMOS inverter (attached). I know that in an NMOS inverter (which has the resistor in top of the transistor instead of the bottom) the equation for Vout is:

Vdd - id*rd.

But how does the resistor being in the bottom change this behavior? Is it now Vcc - ground? (which would equal Vcc).

Thanks.
 
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jean28 said:
It could also be Vout = id * Rd.
If by Rd you mean that external resistor, then that looks right for output logic HIGH.