PMOS Circuit Problem: Finding Rs and Input Resistance

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SUMMARY

The discussion focuses on solving a PMOS circuit problem involving the calculation of source resistance (Rs) and input resistance. The user applied the large signal model and derived Rs as 7500 ohms using the equation Id=K*(Vsg-Vth)², with Vd set to -7.5V and Vg calculated as -7.5V. The user encountered difficulties in determining the input resistance, which resulted in an impossible negative resistance value. The discussion emphasizes the importance of correctly applying voltage division and recognizing the operational characteristics of PMOS transistors, particularly in relation to NMOS equations.

PREREQUISITES
  • Understanding of PMOS transistor operation and characteristics
  • Familiarity with large signal models in circuit analysis
  • Knowledge of voltage division principles in electrical circuits
  • Proficiency in solving equations involving resistances in parallel
NEXT STEPS
  • Study the characteristics and equations specific to PMOS transistors
  • Learn about large signal modeling techniques for MOSFETs
  • Explore voltage division and its applications in circuit analysis
  • Investigate methods for calculating equivalent resistances in parallel circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing PMOS transistor circuits will benefit from this discussion.

DragonChase29

Homework Statement


upload_2017-9-10_21-39-45.png


Homework Equations


  • Id=K*(Vsg-Vth)2
  • KVL

The Attempt at a Solution


On part A,
Haven't had much experience with PMOS. Used large signal model, to find Rs.
Equivalent circuit:
upload_2017-9-10_21-50-1.png


We know that Vs=0. That means Vd=-7.5 V. If we say the voltage across Rs is Vdd-Vd, then that voltage is 22.5 V. Used 22.5V/Id and got 7500 ohms.

Used the Id equation to find Vsg to be 7.5 V

Vsg=Vs-Vg, and Vs=0, so Vg=-7.5

Now,we know there are 2 unknowns, so we need 2 equations. The first equation, we used voltage division to be
  • -7.5=15*(Rg2/(Rg1+Rg2))
Then, the second equation was using the small signal model. The input resistance was the Parallel between Rg1 and Rg2:
  • 3M=((Rg1)-1+(Rg2)-1)-1
  • We disregard the 10km because it is so small in comparision
This is where the problem lies. If we continue, then it leads to a value with negative ohms, which is not possible.

Any help is appreciated.
 
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Since the drain is grounded (if we call the lower supply rail = ground, 0V), then source is +7.5V

With the supply being 0V and +15V, there's a mistake if you calculate a DC voltage anywhere here of 22V. Every DC voltage is going to be within 0V...+15V
 
DragonChase29 said:
Haven't had much experience with PMOS.
PMOS is same as NMOS except polarities are reversed: Vs > Vd and Vg < Vs in normal operation. You can thus use the NMOS equations, e.g i = K(Vs - Vg - |VT|)^2.
 

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