Variation in mass and binding energy in nuclear reactions

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SUMMARY

The discussion focuses on the energetics of nuclear reactions, specifically addressing the correctness of two statements regarding binding energy. Statement A asserts that in a fission reaction, the daughter nuclei possess greater binding energy per nucleon than the original nucleus, while Statement B claims that in a fusion reaction, the heavier nucleus has more binding energy per nucleon than the lighter ones. Both statements are confirmed as correct for energy-releasing reactions, with the understanding that the mass of reactants is always greater than that of products, and the total binding energy of reactants is lower.

PREREQUISITES
  • Understanding of nuclear fission and fusion processes
  • Knowledge of binding energy per nucleon
  • Familiarity with mass-energy equivalence (E=mc²)
  • Basic concepts of kinetic energy in nuclear reactions
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Krushnaraj Pandya
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Homework Statement


I'm perpetually confused keeping track of the energetics of a nuclear reaction and I broke down my conceptual questions into the following parts
statement a-In a fission reaction, the two medium sized daughter nuclei each have more binding energy per nucleon than the original nucleus
statement b-In a fusion reaction the heavier nucleus has more binding energy per nucleon than the lighter ones

Which of these statements are correct and why, I know that mass of the reactants is always higher (the loss in mass is released as energy) and total binding energy of reactants is always lower (I can't visualize this very well) for a spontaneous reaction but I can't figure out the validity of the above statements and I'd really appreciate some help with that-thank you.

Homework Equations


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The Attempt at a Solution


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Both statements are correct for reactions that release energy. There are also reactions that do not. You can e.g. fuse heavy nuclei with an accelerator delivering the necessary energy.
Krushnaraj Pandya said:
and total binding energy of reactants is always lower (I can't visualize this very well)
The sign convention for binding energy is a bit unfortunate.

If in doubt you can always consider the total energy.
 
mfb said:
Both statements are correct for reactions that release energy. There are also reactions that do not. You can e.g. fuse heavy nuclei with an accelerator delivering the necessary energy.The sign convention for binding energy is a bit unfortunate.

If in doubt you can always consider the total energy.
How can we use total energy without using the sign convention for binding energy?
 
Do you mean to say we'd use rest mass*c^2 of reactants+ KE due to any velocity =rest mass of products*c^2 +KE
 
That always works, sure.
 
mfb said:
That always works, sure.
Alright, thank you very much :D
 

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