Correct statement regarding the graph of binding energy per nucleon

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Homework Help Overview

The discussion revolves around the interpretation of a graph related to binding energy per nucleon, specifically focusing on the stability of nuclei and the processes of fusion and fission. Participants are analyzing multiple-choice options regarding the correct statements about the graph and its implications.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants present various options as potentially correct, with some expressing uncertainty about the reasoning behind their choices. Questions arise regarding the implications of binding energy on stability and the processes that lead to the formation of elements beyond iron.

Discussion Status

There is an ongoing exploration of different options, with some participants suggesting that option C is correct while others express confusion about option D. The conversation reflects a lack of consensus, but there is productive engagement with the concepts involved.

Contextual Notes

Participants are navigating the complexities of nuclear stability and the processes of fusion and fission, with some indicating reliance on an answer key that may not align with their interpretations. There is also mention of potential misinterpretations of the question's implications.

songoku
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Homework Statement
The graph below shows how the binding energy per nucleon of a nucleus varies with mass number A
(graph is given below)

Let region P is around mass number equals to 5, region Q is around mass number equals to 50 and region R is around mass number equals to 200

Which one of the following statements is not true?
a. The binding energy per nucleon increases most significantly at lower nucleon numbers
b. Nuclei in region Q are more stable than nuclei in region R
c. Nuclear fusion reaction bring nuclei closer to region Q
d. Energy is released in nuclear fission reactions from nuclei in region R
Relevant Equations
Not sure
Option A is correct because the graph increases sharply at lower nucleon number

Option B is correct because higher binding energy per nucleon means more stable

Option C is correct because either fusion or fission will bring the product to Q

So my guess the answer is D but I do not understand why

Thanks
bindenrg.gif
 
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songoku said:
Option C is correct because either fusion or fission will bring the product to Q
Regardless of the mass numbers of the original atomic species?
 
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haruspex said:
Regardless of the mass numbers of the original atomic species?

Yes I think so
 
songoku said:
Yes I think so
Then how are elements past Iron created?
 
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haruspex said:
Then how are elements past Iron created?
Ah I see. In star the formation of heavier element than iron is through fusion. So the answer should be C.

Thank you very much
 
Sorry haruspex, my friend said the answer to this question is D (based on the answer key)
 
songoku said:
Sorry haruspex, my friend said the answer to this question is D (based on the answer key)
I didn't study D. Yes, that is wrong, but I had not interpreted the question as implying only one was wrong. I believe the correct answer is C and D.
 
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I am sorry for late reply

Why is option D wrong? I think nuclei in region R will be more likely to undergo fission and fission reaction also releases energy

Thanks
 
songoku said:
I am sorry for late reply

Why is option D wrong? I think nuclei in region R will be more likely to undergo fission and fission reaction also releases energy

Thanks
Sorry, I have no idea why I wrote that. Must have misread something.
 
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  • #10
haruspex said:
Sorry, I have no idea why I wrote that. Must have misread something.
So in your opinion C is the answer? Thanks
 
  • #11
songoku said:
So in your opinion C is the answer? Thanks
Yes.
 
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  • #12
haruspex said:
Yes.
Thank you very much haruspex
 

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