Binding energy and favorable reactions

  • #1
6
0
[Moderator note: Thread moved from technical section, thus no template is shown]

Hi everyone!
I'm currently learning nuclear physics and I have a question:
Watching the binding energy per nucleon curve, is the following reaction energetically favorable?
2H + 4He -> 6Li
And why?
500px-Binding_energy_curve_-_common_isotopes.svg.png

Thanks!!!
 

Answers and Replies

  • #2
35,388
11,730
Why don't you take the values from the diagram and check for yourself? Better (more accurate): Look up the binding energies (or the masses) and calculate it.
 
  • #3
6
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Why don't you take the values from the diagram and check for yourself? Better (more accurate): Look up the binding energies (or the masses) and calculate it.
The question asks to answer according to the curve :\
 
  • #4
35,388
11,730
I moved you to the homework section.

Well, then use the diagram and check it.
 
  • #5
6
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I moved you to the homework section.

Well, then use the diagram and check it.
That's exactly my question... The binding energy of the 4He is bigger than the B.E of the product. Is that it? or is there something more?
 
  • #7
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What about the binding energy of deuterium?
well it's smaller! and that is my question!
 
  • #8
35,388
11,730
No, that is the homework question.

What is the combined binding energy of D+4He?
 
  • #9
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No, that is the homework question.

What is the combined binding energy of D+4He?
do you mean for 2H + 4He -> 6Li:
2*1 MeV + 4*7MeV = 30MeV < 6*5.3 = 31.8 therefore the reaction is energetically favorable?
 
  • #10
35,388
11,730
Sure.

To conserve energy and momentum, you would need an additional photon in the final state.
 
  • #11
6
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Sure.

To conserve energy and momentum, you would need an additional photon in the final state.
Thanks for the help! :)
 

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