I Variation of Four-Velocity Vector w/ Respect to Metric Tensor

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The discussion centers on deriving the variation of the four-velocity vector Uμ with respect to the metric tensor gαβ. Rafael seeks assistance in demonstrating that δUμ equals 1/2 UμδgαβUαUβ. A suggestion is made to utilize LaTex for better presentation of equations, as the forum supports MathJax. The responder advises proving the relationship δg^{αβ}UαUβ = 2 UμδUμ first, then applying the condition UμUμ = 1 to facilitate the derivation. The conversation emphasizes the importance of clear mathematical representation in physics discussions.
Hubble_92
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Hi everyone! I'm having some difficulty showing that the variation of the four-velocity,

Uμ=dxμ/dτ

with respect the metric tensor gαβ is

δUμ=1/2 UμδgαβUαUβ

Does anyone have any suggestion?

Cheers,
Rafael.

PD: Thanks in advances for your answers; this is my first post! I think ill be active sharing and discussing in other Physics/ Astrophysics topics ;)
 
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Hubble_92 said:
Hi everyone! [...] PD: Thanks in advances for your answers; this is my first post! I think ill be active sharing and discussing in other Physics/ Astrophysics topics ;)
Just a suggestion for the future. Please, use the LaTex code. This website has MathJax implemented, so that the equations are made to look great. Just search here for a tutorial on how to write with the simple code.
 
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First prove that
\delta g^{\alpha\beta}U_{\alpha}U_{\beta} = 2 U_{\mu}\delta U^{\mu}. \ \ \ \ \ \ \ (1) Then, using U_{\mu}U^{\mu} = 1, you can write the left-hand-side of (1) as
\delta g^{\alpha \beta}U_{\alpha}U_{\beta} \equiv 2 U_{\mu} \left( \frac{1}{2}U^{\mu} \delta g^{\alpha \beta}U_{\alpha}U_{\beta}\right) . \ \ \ \ \ (2)
The result follows by comparing (1) with (2).
 
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