Various RLC Circuit Problems (Resonance Frequency, Phase, Current)

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SUMMARY

This discussion focuses on solving various problems related to an RLC circuit with parameters L = 20mH, R = 20kΩ, and C = 250μF. The resonance frequency was calculated using the formula ω₀ = 1/√(LC), resulting in a frequency of approximately 447.21 Hz. For a frequency of ω = 400 rad/s, the phase angle was determined to be -0.0057° and the impedance calculated as approximately 20000.0001Ω. The current in the circuit was derived as I(t) = 0.0015sin(400t), and participants sought guidance on drawing the phasor diagram for t=0 seconds.

PREREQUISITES
  • Understanding of RLC circuit components (Resistor, Inductor, Capacitor)
  • Familiarity with phasor diagrams in AC circuit analysis
  • Knowledge of trigonometric functions and their applications in electrical engineering
  • Ability to perform calculations involving complex numbers and impedance
NEXT STEPS
  • Study the derivation and implications of the resonance frequency formula ω₀ = 1/√(LC)
  • Learn how to analyze phase angles in RLC circuits using the formula ϕ = tan⁻¹[(Xₗ - Xc)/R]
  • Explore the concept of impedance in AC circuits and its calculation Z = √(R² + (Xₗ - Xc)²)
  • Investigate methods for constructing phasor diagrams and their significance in circuit analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in the analysis of RLC circuits will benefit from this discussion, particularly those looking to deepen their understanding of resonance, phase relationships, and impedance in AC circuits.

Spaghetti
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Homework Statement


An RLC circuit has L = 20mH, R = 20kΩ, C = 250μF.

1) Calculate the resonance frequency for this circuit.

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

4) Draw the phasor diagram for t=0 seconds.

Homework Equations


ω_{o} = \frac{1}{\sqrt{LC}}

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL

X_{C} = \frac{1}{ωC}

Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

I(t) = \frac{ε}{Z}

The Attempt at a Solution


So I wasn't sure if I was doing any of this correctly; with all of the formulas/equations, it looked like the questions were mostly some simple plug-in questions, but I feel like my numbers just weren't coming out quite right.

1) Calculate the resonance frequency for this circuit.

ω_{o} = \frac{1}{\sqrt{LC}}
L = 20mH = 0.02H; C = 250μF
ω_{o} = \frac{1}{\sqrt{(0.02H)(250μF)}} = \frac{1}{2.24 sec} = 0.447 Hz

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.
Phase Angle ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL = (400)(0.02) = 8
X_{C} = \frac{1}{(400)(250)} = \frac{1}{100,000} = 0.00001
R = 20kΩ

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-0.00001}{20,000}\right] = tan^{-1} \left[\frac{7.99999}{20,000}\right] = tan^{-1} \left[3.99x10^{-4}\right] = 0.0229°

Impedance Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 0.00001)^{2}} = \sqrt{4.0x10^{8} + 63.99} = 20000.0016Ω

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

I(t) = \frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = 0.00149sin(400t)

So I(t) = 0.00149sin(400t)

4) Draw the phasor diagram for t=0 seconds.

I wasn't sure at all how to go about doing this one. As far as I can tell, this one ends up being a graph with voltage and current functions (current found in #3) drawn at t=0, showing how out of phase they are at that time, although I'm not sure how to find the voltage/what to use to find it. Of course, I don't want anyone to draw the graph for me, but some advice on phasor diagrams in general/a push in the right direction would be very nice.

Any help would be greatly appreciated. Thank you in advance!
 
Last edited:
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The capacitance is given in microfarads: C=250 *10-6 F. Repeat the calculations.

ehild
 
Alrighty. I guess my mind totally drew a blank around that capacitance. :blushing:

I feel a lot better about the frequency now; I'm hoping the others are okay, too.

1) Calculate the resonance frequency for this circuit.
ω_{o} = \frac{1}{\sqrt{LC}}
L = 20mH = 0.02H; C = 250x10^{-6}F
ω_{o} = \frac{1}{\sqrt{(0.02H)(250x10^{-6}F)}} = \frac{1}{.00223 sec} = 447.21 Hz

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.
Phase Angle ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL = (400)(0.02) = 8
X_{C} = \frac{1}{(400)(250x10^{-6})} = \frac{1}{.1} = 10
R = 20kΩ

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-10}{20,000}\right] = tan^{-1} \left[\frac{-2}{20,000}\right] = tan^{-1} \left[-1.0x10^{-4}\right] = -0.0057°

Impedance Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 10)^{2}} = \sqrt{4.0x10^{8} + 4} = 20000.0001Ω

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

I(t) = \frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = 0.0015sin(400t)

So I(t) = 0.0015sin(400t)

4) Draw the phasor diagram for t=0 seconds.
I'm still a little confused about this phasor diagram, but I think I can get by. Again, if anyone could offer a little advice on this, it would be great.

And thank you for catching my mistake, ehild.
 

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