Vector calculus and force field

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Homework Help Overview

The discussion revolves around evaluating the work done against a force field described by a vector function in a two-dimensional linear oscillator context. Participants are tasked with comparing work done along different paths between specified points in the force field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of conservative vector fields and their implications for the problem. Questions arise about the notation used in the force field description and its interpretation. There are attempts to clarify the mathematical expressions for work along specific paths.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the notation and the implications of the force field being conservative. Some guidance on the nature of conservative fields has been suggested, but no consensus has been reached regarding the best approach to the problem.

Contextual Notes

There is some uncertainty regarding the notation used for the force field, with participants questioning whether it aligns with standard vector notation. Additionally, the intent of the exercise may involve deeper exploration of the paths and their respective work calculations.

tibphysic
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1.10.1 The force field acting on a two-dimensional linear oscillator may be described by
F=−ˆxkx − ˆyky.
Compare the work done moving against this force field when going from (1, 1) to (4, 4)
by the following straight-line paths:
(a) (1, 1)→(4, 1)→(4, 4)
(b) (1, 1)→(1, 4)→(4, 4)
(c) (1, 1)→(4, 4) along x = y.
This means evaluating

(4,4)
(1,1)
F · dr
along each path.
 
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hi tibphysic, welcome to pf, the idea is to have a try

do you know about conservative vector fields?
 
yes i do.. conservative vectors fields does not depend on the path taken.. just on the initial and the final point.
 
could be useful...
 
tibphysic said:
1.10.1 The force field acting on a two-dimensional linear oscillator may be described by
F=−ˆxkx − ˆyky.

I'm not familiar with that notation. Is that <-kx, -ky> or something else? Are ^x and ^y notations for i and j?
 
lanedance said:
could be useful...

True, but perhaps the intent of the exercise is to actually work them...
 
im assuming his notation ^x , read x hat. where the carrot should be over the x.
is equivalent to i , j , k . they use x hat and y hat and z hat in physics more.
 
For instance:

Along the path (1, 1)→(4, 1), [itex]d\hat{r}=\hat{x}\,dx\,.[/itex]

So, find [itex]\displaystyle\int_{(1,1)}^{(4,1)}\,dW=\int_{x=1}^{x=4}{\vec{F}\,|_{y=1}\cdot\hat{x}}\,dx[/itex]
 
Last edited:
yeah I thought the notation was a little strange but took them as unit vectors, so the potentials were of harmonic oscillator form
 
  • #10
SammyS said:
For instance:

Along the path (1, 1)→(4, 1), [itex]d\hat{r}=\hat{x}\,dx\,.[/itex]

So, find [itex]\displaystyle\int_{(1,1)}^{(4,1)}\,dW=\int_{x=1}^{x=4}{\vec{F}\,|_{y=1}\cdot\hat{x}}\,dx[/itex]
True, but if the force field is conservative, as lanedance suggested in the first response, the problem is much easier. You don't need to do all those integrals.
 

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