Find the volume V of the solid under the surface z=4-x^2-y^2 and over the rectangle R consisting of all points (x,y) such that 0<=x<=1 and 0<=y<=2.(adsbygoogle = window.adsbygoogle || []).push({});

I have started, but am unsure if my approach is correct or not.

x = 4-x^2-y^2

[tex]\int^{2}_{0}\int^{1}_{0} 4-x^{2}-y^{2} dx dy[/tex]

is this correct?

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# Vector calculus double integrals

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