Vector equation of line segment

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Homework Help Overview

The discussion revolves around the vector equation of a line segment, specifically the equation r=(1-t)r0+tr1, where r0 and r1 are the endpoints of the segment. Participants are exploring the implications of the parameter t, particularly why it is typically constrained between 0 and 1.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are examining the derivation of the line segment equation and questioning the necessity of the t parameter being within the range of [0,1]. Some suggest alternative ranges for t and discuss the implications of choosing values outside this range.

Discussion Status

The discussion is active, with participants providing varying perspectives on the constraints of t. Some have offered insights into the convenience of the [0,1] range, while others are exploring the implications of selecting t values outside this range. There is no explicit consensus yet, but the conversation is probing deeper into the assumptions behind the equation.

Contextual Notes

Participants are considering the implications of extending the value of t beyond the conventional range and discussing how this affects the identification of points on the line segment versus the extended line. There are also references to the need for clarity in questions posed regarding the topic.

nameVoid
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my text explains that a line segment is given by the equation r=(1-t)r0+tr1
such that 0<=t<=1

now i see how this formula is derived however i am not clear on why t must be between 0 and 1 if this is the equation for a line segment
 
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t is chosen in [0,1] so that ro and r1 are the endpoints. We can take t in [a,b] then we have
r=(a+b-t)r0+tr1
then the endpoints are
br0+ar1
ar0+br1
 
if i were to derive this formula
so we have

vector r0 and vector r1 and want the equation of the line through the tip of r and r1 well in this case we can take the direction vector to be r1-r0 and replacing v with this in the equation r=r0+tv we have r=r0+t(r1-r0) and the we have r=r0(1-t)+tr1 this should work for any two vectors from the origin to the line why does the value of t need to be between 0 and 1
 
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It does not need to be between 0 and 1 it is just convenient we can have

$$t \in [a,b] \\ \vec{r}=\vec{r_0}+\left( \frac{t-a}{b-a} \right) ^{192435341024} \vec{r_1}$$

we can have the probability of getting heads when flipping a coin be 137.
It is convenient to consider [0,1] so that the value equals the ratio.
Nothing more nothing less.
 
what if we are to choose a value of t that point outside of the segment how are we to know what values of t are contained within the segment
 
Your question isn't clearly stated. If t is negative or greater than 1, then we are identifying a point on the extended line segment. So what is the question you want clarified?
 
nameVoid said:
what if we are to choose a value of t that point outside of the segment how are we to know what values of t are contained within the segment
Consider the distances from r = r0+t(r1-r0) to each of r0, r1. For r to be on the line segment, each distance must be <= |r1-r0|. What range does that give for t?
 
ok this makes sense here we plug the the vectors into the equations and solve for t i see
 
i have also posted another question about distance between lines
 

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