Vector Spaces: Verify whether a set is a vector space

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SUMMARY

The discussion centers on determining whether the set of vectors (u, v) where u + v = 0 qualifies as a vector space. The conclusion reached is that this set does indeed form a vector space, as it satisfies the necessary axioms, particularly the existence of the zero vector and closure under addition and scalar multiplication. The participant struggles with understanding the axioms, particularly the sixth axiom regarding scalar multiplication, which is crucial for confirming the vector space properties.

PREREQUISITES
  • Understanding of vector space axioms, specifically the 10 axioms of vector spaces.
  • Familiarity with vector addition and scalar multiplication operations.
  • Knowledge of the concept of the zero vector in vector spaces.
  • Basic algebraic manipulation skills to work through vector equations.
NEXT STEPS
  • Study the 10 axioms of vector spaces in detail to understand their implications.
  • Learn about the properties of the zero vector and its role in vector spaces.
  • Explore examples of vector spaces to see how the axioms are applied in practice.
  • Review scalar multiplication and its significance in vector space theory.
USEFUL FOR

Students studying linear algebra, educators teaching vector space concepts, and anyone seeking to deepen their understanding of vector space properties and axioms.

lawlbus
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I was given a set of problems and answers, but not the solutions. This is one of the questions I've been having trouble in getting the correct answer.

Homework Statement


Determine whether the set of vectors (u, v) is a vector space, where u + v = 0.

Homework Equations


The 10 axioms of vector space.

The Attempt at a Solution


The correct answer to this problem is TRUE, but I must be doing something wrong because I'm getting FALSE. I'm not quite sure if what I'm doing is right:

i) Both u and v are in V, and u + v is in V. (I'm not positive on this... is 0 always in V?)

ii) u + v = v + u (True)

iii) (u + v) + w = u + (v + w) (Not sure how to use the vector w in this one.. but it should be true if u + v = 0 as defined, right?)

iv) 0 + u = u + 0 = v (true)

v) u + (-u) = (-u) + u = u + v = 0 (true)

vi) c*u exists in V (false...? VERY UNSURE on this one! I thought it was false because of this!)

vii) c(u + v) = cu + cv (true)

viii) (c + d)u = cu + du (true)

ix) c(du) = (cd)u (true)

x) 1 * u = u (true)


I think my trouble is I'm not sure of the context on what V consists of.
 
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I'm not sure what's your axiom vi) supposed to mean?
 

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