Find a vector that has the same direction as <-2, 4, 2> but has length 6.
Length of vector in 3D = |v| = (x2 + y2 + z2)0.5
The Attempt at a Solution
I can see that the length of the given vector is (-2)2 + 42 + 22 = 24
36 is (1.5)24, so I tried multiplying each component of the vector by the scalar 1.5. However, this doesn't give me the desired length of six (rather, it gives me the square root of 54). I had a feeling this method would be faulty, but nothing else comes to mind.