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## Homework Statement

In the sum A+B = C, vector A has a magnitude of 10.0 m and is angled 46.5° counterclockwise from the +x direction, and vector C has a magnitude of 15.0 m and is angled 23.5° counterclockwise from the -x direction. What are the magnitude and the angle (relative to +x) of B?

________ m at _______ ° counterclockwise from the +x direction

## Homework Equations

a

^{2}+b

^{2}=c

^{2}

## The Attempt at a Solution

I have tried this:

A: (10cos(46.5))= 6.88; (10sin(46.25))= 7.25

C: (15cos(23.5))= 13.76; (15sin(23.5))= 5.98

Then:

13.76-6.88= 6.88

5.98-7.25=-1.27

After this I used the Pythagorean Theorem...

√(-1.27)

^{2}+(6.88)

^{2}= 7m

However, this answer is incorrect.

From there I calculated tan

^{-1}(-1.27)/(6.88)= -10.46 degrees

Also obviously incorrect.

Help is greatly appreciated!