Vectors: Solving a Trajectory on the x-y Plane

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Homework Help Overview

The problem involves analyzing the trajectory of a point mass under the influence of two forces in the x-y plane, specifically focusing on the integration of acceleration to determine position over time.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the total force acting on the mass and the need to integrate the acceleration to find the trajectory. There is confusion regarding the terminology of the x-y plane versus the i,j notation used for unit vectors.

Discussion Status

Some participants clarify the relationship between the unit vectors and the x-y plane, while others explore the process of separating the components of acceleration for integration. There is a general agreement on the approach to take, but no explicit consensus on the final steps.

Contextual Notes

Participants are navigating the integration process and the interpretation of vector notation, with some expressing uncertainty about the terminology used in the problem statement.

discombobulated
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[SOLVED] vectors -

Homework Statement



At time t = 0 two forces f1 = (i + j) and f2 = (2i - 2j) start acting on a point body of unit mass lying stationary at the point (1,2) of the x,y plane. Describe the trajectory r(t) of the plane.

Homework Equations



F = ma

a = d2x/dt2

The Attempt at a Solution



Total force, F = (i + j) + (2i - 2j)
F = (3i - j)

I know I need to integrate using the acceleration equation but I'm confused by the x,y plane, I thought it was meant to be in i,j plane? :S Could someone please explain?
Thanks!
 
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i and j are unit vectors in the direction of the positive x and positive y direction respectively, so you're still working in the x-y plane.
 
thanks, so do i split it like this, d2x /dt2 = 3 and d2y /dt2 = -1 and then when I integrate to get x and y, put it back into i and j form?
 
discombobulated said:
thanks, so do i split it like this, d2x /dt2 = 3 and d2y /dt2 = -1 and then when I integrate to get x and y, put it back into i and j form?
Sounds good to me :approve:
 

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