Velocity and height of an arrow

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SUMMARY

The discussion focuses on calculating the velocity and height of an arrow using physics principles. The spring constant (k) is given as 898 N/m, the mass (m) is 0.0907 kg, and the distance (d) is 0.6558 m. The formula derived for velocity is v = √(2gh), where g is the acceleration due to gravity (9.8 m/s²). The calculated velocity of the arrow is 65.3 m/s, demonstrating a successful application of the physics equations involved.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of potential and kinetic energy
  • Knowledge of basic algebra and square root calculations
  • Experience with physics equations related to motion
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  • Study the principles of energy conservation in mechanical systems
  • Learn about projectile motion and its equations
  • Explore the effects of air resistance on projectile velocity
  • Investigate the relationship between spring constants and potential energy
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of projectile motion and energy conversion.

the whizz
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would like to see if this looks rite before bed...due tomorrow
 
This is great because I was just having trouble calculating velocity tonight and finally figured it out.

You've got the height right and a short cut I discovered to finding velocity is
that velocity equals the square root of 2xgxh

v=\sqrt{}2gh so v=\sqrt{}2x9.8x217.55

v=65.3m/s
 

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