Velocity of Comet at a given distance

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Halley’s Comet, with a closest approach speed of 54.6 km/s at 9×10^7 km from the sun, is being analyzed for its speed at the orbit of Neptune, approximately 5 billion kilometers away. The discussion centers on using the conservation of energy principle to calculate this speed, but the original poster is confused by their result of 8.3 km/s, which contradicts the expected 0.8 km/s. Participants suggest that showing the calculations could help identify errors, emphasizing that conservation of energy should yield the correct result. The conversation indicates a consensus that while energy conservation is applicable, careful attention to the calculations is necessary for accuracy.
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Homework Statement


Halley’s Comet travels in a highly eccentric (non-circular) orbit. At its closest approach, it is about 9×10^7 km away from the sun and travels with a speed of 54.6 km/s. What is the comet’s speed when it crosses the orbit of Neptune, about 5 billion kilometres from the sun?

Homework Equations



Conservation of Energy, Ei = Ef

The Attempt at a Solution



I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.
 
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Hamish Taylor said:
I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.
We might be better able to find errors in your work if you were to show your work. Set angular momentum to one side and show us one attempt at a conservation of energy approach.
 
Hamish Taylor said:

Homework Statement


Halley’s Comet travels in a highly eccentric (non-circular) orbit. At its closest approach, it is about 9×10^7 km away from the sun and travels with a speed of 54.6 km/s. What is the comet’s speed when it crosses the orbit of Neptune, about 5 billion kilometres from the sun?

Homework Equations



Conservation of Energy, Ei = Ef

The Attempt at a Solution



I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.

You are right, conservation of energy should work. I got nearly the same result as you.
 
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