1. The problem statement, all variables and given/known data Tony has a tendency to drop his bowling ball on the floor at the completion of his follow-through swing. Tony lets the ball go when the ball is 0.28m above the floor. If the ball travels a horizontal distance of 1.80m before you hear a "thud", with what velocity did Tony throw the bowling ball? 2. Relevant equations dv=1/2*at2 dh=Vh*Δt Kinetic equation d=Vi*t+ 1/2*at2 dh=-V2*sin2θ /g 3. The attempt at a solution dv=0.28m dh=1.80m Vh=? Solve for t and found that t=4.18s by rearranging the dv equation. Then that value was plugged into the dh equation and rearranged to solve for Vh, to give Vh=0.43m/s. I would like for someone to just verify my answer and check that the significant figures are being respected. Thanks so much in advance!