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dani123
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Homework Statement
Tony has a tendency to drop his bowling ball on the floor at the completion of his follow-through swing. Tony let's the ball go when the ball is 0.28m above the floor. If the ball travels a horizontal distance of 1.80m before you hear a "thud", with what velocity did Tony throw the bowling ball?
Homework Equations
dv=1/2*at2
dh=Vh*Δt
Kinetic equation d=Vi*t+ 1/2*at2
dh=-V2*sin2θ /g
The Attempt at a Solution
dv=0.28m
dh=1.80m
Vh=?
Solve for t and found that t=4.18s by rearranging the dv equation.
Then that value was plugged into the dh equation and rearranged to solve for Vh, to give Vh=0.43m/s.
I would like for someone to just verify my answer and check that the significant figures are being respected. Thanks so much in advance!