Velocity Ratio in Gears & Wheels Systems: Inverting?

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Discussion Overview

The discussion revolves around the concept of velocity ratio in gears and wheels systems, specifically addressing whether the velocity ratio should be inverted when considering the number of teeth on gears. Participants explore the definitions and implications of velocity ratio in relation to mechanical advantage and torque.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose that the velocity ratio is defined as the distance traveled by the effort divided by the distance traveled by the load, questioning if this definition changes when applied to gears.
  • Others argue that for gears, the velocity ratio should be calculated as the diameter or number of teeth of the input gear divided by that of the output gear, emphasizing the need to understand the specific definitions used in different contexts.
  • A participant notes that the velocity ratio for gears will always be lower than the mechanical advantage due to factors like dead weight and friction.
  • Another participant expresses confusion regarding the inversion of the velocity ratio as presented in a book, suggesting that careful reading may clarify the relationship between input and output torque and the distances moved by the gears.
  • There is a suggestion that if the book contains errors, it is important to verify the results independently rather than relying solely on potentially unclear texts.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the inversion of the velocity ratio in gears, with multiple interpretations and understandings of the definitions and calculations involved remaining in contention.

Contextual Notes

Limitations in the discussion include potential ambiguities in the definitions of velocity ratio and mechanical advantage, as well as the unclear presentation of information in the referenced book.

Crissy
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Hi, if the velocity ratio is equal to the distance traveled by the effort divided by the distance traveled by the load, in a gears and wheels system, do you invert that in the case or gears? Making it number of teeth on driven gear divided by number of teeth on driving gear? Thanks
 

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Crissy said:
Hi, if the velocity ratio is equal to the distance traveled by the effort divided by the distance traveled by the load, in a gears and wheels system, do you invert that in the case or gears? Making it number of teeth on driven gear divided by number of teeth on driving gear? Thanks
It's exactly the same but you need to read the small print about what VR really means. The velocity ratio is the diameter (or number of teeth) of the input wheel divided by the diameter of the output wheel. That follows the definition. You cannot compare it with the way VR is calculated for levers because, with rigid levers it's the angle change that stays the same but, for gears in mesh, it's the tangential distance.

It will always be lower than the Mechanical advantage due to dead weight and friction etc.
 
Thanks for ur reply. So how come in book it inverts it? I dnt quite understand
 

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Crissy said:
Thanks for ur reply. So how come in book it inverts it? I dnt quite understand
I can't read what the book actually says - it's too blurry with no contrast. But I think, if you read the book carefully (as I cannot) then you should find the distance moved by the Input and output teeth is the same but the input torque is Input Forcein times its radius and the output torque is Forceout times its radius. If you are still confused then, rather than trying to make sense of the book, work it out independently. Unless the book is actually wrong (never impossible to find a typo) your final result will agree with it.
Apply the 'does to make sense?' test against your experience of gears.

PS Read my earlier post again and digest the message; it shows how one could get things back to front.
 

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