A person throws a ball with 13,5 m/s straight up. Calculate the maximum height that it will reach from the point where it was thrown. Also find the velocity when the ball is 1.50m above the starting point.
Sorry if the problem is hard to understand, had to translate it from spanish, hopefully it's clear enough.
Vx = V0x + axt
x = x0 + v0xt + 1/2 ax t^2
The Attempt at a Solution
13.5m/s = 0 + 9.81 * t
13.5/9.81 = t
t = 1.38 s (what it took to reach the highest point)
x = 0 + 13.5 * 1.38 + 1/2 * -9.81 * 1.37^2
x = 9.42 m (maximum height?)
Not sure if the problem is correct, if it's not any guidance is appreciated. I'm also missing what's the velocity 1.50m above the starting point.