- #1

pressurised

- 22

- 0

## Homework Statement

## Homework Equations

p=ρgh

Q=A

_{1}U

_{1}=A

_{2}U

_{2}

Bernoulli:

p

_{1}+½ρU

_{1}

^{2}+ρgz

_{1}=p

_{2}+½ρU

_{2}

^{2}+ρgz

_{2}

## The Attempt at a Solution

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So I got that the pressure difference is gh(ρ

_{m}-ρ). So I rearranged Bernoulli for p

_{1}-p

_{2}to get (assuming the potential is the same I eliminated it),

p

_{1}-p

_{2}=½ρU

_{2}

^{2}-½ρU

_{1}

^{2}

I carried on rearranging to get:

√(2gh(ρ

_{m}-ρ))/ρ = Q/A

_{2}-Q/A

_{1}

I am unsure how to eliminate A

_{1}so I can proceed with the question