- #1
Yaridovich
- 5
- 0
I was looking at the moment of inertia list that they have on Wikipedia and noticed that the moment of inertia for a regular polygon was rather complicated. I did the calculation myself and found a significantly simpler result of
I = (m/6)(3+tan(pi/n)^2)*R^2:
m is the mass of the polygon,
n is the number of edges of the polygon,
R is the length of the line segment from the center of the polygon to one of its edges, where the line segment is perpendicular to that edge. I just wanted to verify that this is correct; I can submit a proof of how I calculated this if need be.
I = (m/6)(3+tan(pi/n)^2)*R^2:
m is the mass of the polygon,
n is the number of edges of the polygon,
R is the length of the line segment from the center of the polygon to one of its edges, where the line segment is perpendicular to that edge. I just wanted to verify that this is correct; I can submit a proof of how I calculated this if need be.