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Verify that the function satisfies the hypotheses of the Mean Value Theorem on the given interval. Then find all numbers that satisfy the conclusion of the Mean Value Theorem.
f(x)=3x^2+6x+7 on [-2,3]
so f(3)-f(-2)=f'(x)(3+2)
i get 52-7=(6x+6)(5)
then 45=30x+30
then 5=30x
and x=1/6
where am i going wrong?
f(x)=3x^2+6x+7 on [-2,3]
so f(3)-f(-2)=f'(x)(3+2)
i get 52-7=(6x+6)(5)
then 45=30x+30
then 5=30x
and x=1/6
where am i going wrong?