Verify Multivariable Limits w/ Delta-Epsilon Arguments

Click For Summary
SUMMARY

The discussion focuses on verifying the multivariable limit of the function lim (x, y) -> (1, -1) of xy^2 = 1 using delta-epsilon arguments. The participant expresses difficulty in applying delta-epsilon proofs, particularly when the limit is a constant rather than zero. Key insights include the use of the inequality sqrt(x^2 + y^2) < delta to establish |f(x,y) - L| < epsilon, which leads to the expression |xy^2 - 1| = |(xy^2 - y^2) + (y^2 - 1)| as a starting point for simplification.

PREREQUISITES
  • Understanding of delta-epsilon definitions in calculus
  • Familiarity with multivariable limits
  • Basic algebraic manipulation skills
  • Knowledge of inequalities and their applications in proofs
NEXT STEPS
  • Study delta-epsilon proofs for multivariable limits in detail
  • Practice simplifying expressions involving constants in limits
  • Explore examples of limits that equal zero versus non-zero constants
  • Learn about continuity and differentiability in multivariable calculus
USEFUL FOR

Students studying calculus, particularly those tackling multivariable limits, educators teaching limit concepts, and anyone seeking to strengthen their understanding of delta-epsilon arguments.

Volt
Messages
10
Reaction score
0

Homework Statement



Verify the following limit by using delta-epsilon arguments

Homework Equations



lim (x, y) -> (1, -1) of xy^2 = 1

The Attempt at a Solution



Right, so I'm having some trouble with these delta-epsilon proofs for multivariable limits. Some of them are easier than others; I'm talking mainly about cases where the limit = 0, when the limit is some other constant like in the above question I'm not sure how to simplify it and try to get an answer.

I'm aware of some of the basic ideas here, like:

sqrt(x^2 + y^2) < delta => |f(x,y) - L| < epsilon

This also implies that |x| < delta and |y| < delta, which seems to be what you use in practice to solve most of these things, rather than the above definition.

If I try that on the above equation though, I get |delta^3 - 1| < epsilon. What on Earth do I do from here? How do I deal with the constant in situations like these?
 
Physics news on Phys.org
Hint: Try writing |xy2 -1| = |(xy2 - y2) + (y2 - 1)| to get started.
 

Similar threads

  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 15 ·
Replies
15
Views
6K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K