Verifying Homework Equations: 4 Variables

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
temaire
Messages
275
Reaction score
0

Homework Statement



rc7qe9.png


Homework Equations



[tex]\tau=\frac{4V}{3A}[/tex]

[tex]\sigma_b=\frac{-Mc}{I}[/tex]

[tex]\tau=\frac{Tr}{J}[/tex]

[tex]J=\frac{\pi r^4}{2}[/tex]

[tex]I=\frac{\pi r^4}{4}[/tex]

The Attempt at a Solution



a)
2us7hg2.png


[itex]-V(x) + R_y = 0[/itex]
[itex]V(x) = R_y[/itex]
[itex]V(x) = 1000[/itex]

[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]

[itex]T(x) = P(0.4)[/itex]
[itex]T(x) = 400[/itex]

ddi683.png


[itex]V(x) - 1000 = 0[/itex]
[itex]V(x) = 1000[/itex]

[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]

[itex]T(x) = 0[/itex]

b)
[tex]\tau_{max} = \frac{4V}{3A}[/tex]

[tex]\tau_{max} = \frac{4*1000}{3*\pi*0.12^2}[/tex]

[tex]\tau_{max} = 29.5 KPa[/tex]

Coordinates: From (0,-0.12,0)m to (0,0.12,0)m

c)
[tex]\sigma_b=\frac{Mc}{I}[/tex]

[tex]\sigma_b=\frac{Mc}{\frac{\pi r^4}{4}}[/tex]

[tex]\sigma_b=\frac{1000*0.4*0.12}{\frac{\pi * 0.12^4}{4}}[/tex]

[tex]\sigma_b=294.7 KPa[/tex]

[tex]\sigma_{Max,tensile}=294.7 KPa[/tex] at (0,0,0.12)m

[tex]\sigma_{Max,compressive}=-294.7 KPa[/tex] at (0,0,-0.12)m

d)
[tex]\tau=\frac{Tr}{J}[/tex]

[tex]\tau=\frac{Tr}{\frac{\pi r^4}{2}}[/tex]

[tex]\tau=\frac{1000*0.4*0.12}{\frac{\pi *0.12^4}{2}}[/tex]

[tex]\tau=147.4 KPa[/tex]

Coordinates: From (0,-0.12,0)m to (0,0.12,0)m


Is my work correct?
 
Physics news on Phys.org
Guys, I have a final exam on this material tomorrow. Any help would be appreciated.