Verifying Subring: Check Closure with ℂ & \alpha

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SUMMARY

The discussion focuses on verifying that the set R = {x + yα | x, y ∈ Z} is a subring of the complex numbers ℂ, where α = (1 + √-3)/2. Participants highlight that multiplying two elements of R results in the negative complex conjugate of α, leading to confusion regarding closure properties. The negative complex conjugate is calculated as -α̅ = α - 1, indicating that the original concern about closure may stem from misunderstanding the properties of complex conjugates in this context.

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For [itex]\alpha = (1+ \sqrt{-3})/2 \in ℂ[/itex] and [itex]R = \{ x +y\alpha \, | \, x,y \in Z \}[/itex].

How would you verify that R is a subring of ℂ? Everytime I multiply two 'elements' of R to check closure I get the negative complex conjugate of [itex]\alpha[/itex], I think I'm doing something wrong...

Thanks!
 
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blahblah8724 said:
For [itex]\alpha = (1+ \sqrt{-3})/2 \in ℂ[/itex] and [itex]R = \{ x +y\alpha \, | \, x,y \in Z \}[/itex].

How would you verify that R is a subring of ℂ? Everytime I multiply two 'elements' of R to check closure I get the negative complex conjugate of [itex]\alpha[/itex], I think I'm doing something wrong...

Thanks!

Let's see...

The negative complex conjugate of ##\alpha## is:
$$-\overline{\alpha} = - \frac 1 2 (1 - \sqrt{-3}) = \frac 1 2 (1 + \sqrt{-3}) - 1 = \alpha - 1$$

What exactly is the problem?
 

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