Vertical motion with constant acceleration

AI Thread Summary
A research balloon with a total mass of 410 kg is descending with a downward acceleration of 1.0 m/s² and needs to achieve an upward acceleration of 1.6 m/s² by releasing ballast. The weight of the balloon is calculated to be 4018 N. The equations used include B - w = m*a and w = mg, leading to the conclusion that 3608 N of buoyant force is required for the upward acceleration. A calculation error was identified in the algebra, indicating that the correct relationship should be 3608 = 11.4m₂. The final mass of ballast to be released is determined to be approximately 201.2 kg after correcting the calculations.
Kajayacht
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Homework Statement


A research balloon of total mass 410 kg is descending vertically with a downward acceleration of 1.0 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.6 m/s2, presuming that the upward lift of the balloon does not change.


Homework Equations


B-w=m*a
w=mg

The Attempt at a Solution



w= 410*9.8
w= 4018 N

B-4018 = 410*-1
B=3608

3608-m{2}*9.8= m{2}*1.6
2255= m{2}+9.8m{2}
2255= 10.8m{2}
m{2} = 208.80
410-208.80= 201.2kg
 
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Kajayacht said:

Homework Statement


A research balloon of total mass 410 kg is descending vertically with a downward acceleration of 1.0 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.6 m/s2, presuming that the upward lift of the balloon does not change.


Homework Equations


B-w=m*a
w=mg

The Attempt at a Solution



w= 410*9.8
w= 4018 N

B-4018 = 410*-1
B=3608

3608-m{2}*9.8= m{2}*1.6
2255= m{2}+9.8m{2}your algebra is wrong. Should be 3608 = 11.4m{2}[/color]
2255= 10.8m{2}
m{2} = 208.80
410-208.80= 201.2kg
Your method is good. Check your math error as noted above.
 
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