1. The problem statement, all variables and given/known data A body is dropped from a height of 300 m. At exactly the same moment another body is projected from the ground vertically upwards with a velocity of 150 m.s^-1. Calculate the … 3.2.1 time it will take for the two objects to reach the same height. 3. The attempt at a solution delta x = vi*t + 1/2*g*t^2 for falling body: delta x = 1/2*g*t^2.............1 for projected body: 300 - delta x = 150t - 1/2*g*t^2..........2 1+2 300 = 150t t = 2's Okay, so I know I will have to solve this simultaneously. I cheated a bit and got this answer from the memo, but I dont understand the second equation, which is the part about the 300 - deltax. Isn't delta x the same for both?, or is it because one is thrown up and the other down which is why they are not the same?, can somebody please explain the second equation to me, especially the 300 - deltax?