I am reading through this text(adsbygoogle = window.adsbygoogle || []).push({});

http://www.ita.uni-heidelberg.de/~dullemond/lectures/tensor/tensor.pdf

and am having a bit of trouble with one of the arguments that is put in index notation. Specifically, equation (3.3). I was wondering if anyone could have a look at it and clear up a confusion for me.

I understand the argument, i.e. that the 'old definition' (eqn (3.2) in the text) of the inner product is not invariant under coordinate transformation in general, which is why we need covectors, covariant components, etc.

My specific question is about how the index notation is used in eqn (3.3). The authors write that

s' = <a',b'> = A^{μ}_{α}a^{α}A^{μ}_{β}b^{β}= (A^{T})^{μ}_{α}A^{μ}_{β}a^{α}b^{β}(3.3)

They then argue that this shows that only if A^{-1}= A^{T}(so the 2 matrices together equal δ_{βα}) (i.e. only if the transformation is orthonormal) will the inner product actually come out to the same value that it had in the untransformed coordinate system.

My question is how to express the inverse and transpose of a matrix in index notation. Where did the transpose come from in the 3rd equality, and why did the indices on it not change position at all? How is the relationship between a matrix, its transpose, and its inverse expressed in index notation? How, exactly, do the authors read off from (3.3) the fact that A^{-1}must equal A^{T}?

I do understand that, to complete the argument, we ultimately need α = β, but how does one get, in practice, from 2 matrices to the Kronecker delta? What would the multiplication of a matrix by its inverse to get the Kronecker delta actually look like when written out?

I understand the argument, but I need clarification on how the argument is being expressed specifically using index notation.

Thanks for any help you can give!

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# Very specific question about index notation

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