Try YouTube. They have lots of math videos.
But here is an example I will make up.
Find the centroid of the semicircular region with radius a centered at the origin.
By symmetry, the x-coordinate of the centroid is 0 since the y-axis is a line of balance.
\overline{y}=\frac{1}{\text{area of region}}\int\int_{R}ydA
The area of a semicircle is \frac{{\pi}a^{2}}{2}
So, we get, using polar coordinates and the fact that y=rsin{\theta}
\frac{2}{a^{2}{\pi}}\int_{0}^{\pi}\int_{0}^{a}r^{2}sin{\theta}drd{\theta}=\frac{4a}{3\pi}
So, the centroid is \left(0,\frac{4a}{3\pi}\right)
Let's say the radius is a=1, then the coordinates of the centroid would be
(0,.4244)