1. The problem statement, all variables and given/known data Show that V across Resistor Rkohms is: (11R) / (3.96 + 4R) V The circuit is a 5V cell in series with a 1.8k resistor. Following the 1.8k resistor are a 2.2k and Rk resistor in parallel with eachother. The wires then rejoin and return to the cell. Current through the circuit has already been found as 5(2.2 + R) / (3.96 + 4R) mA 2. Relevant equations I = V/R 3. The attempt at a solution I = 5(2.2 + R) / (3.96 + 4R) thus I through R = 5(2.2 + R) / (3.96 + 4R) * (R / 2.2 + R) <= Current is divided proportionally to the strength of the resistor. = 5R / (3.96 + 4R) <= Simplification. V = IR thus V across R = (5R / 3.96 + 4R)) * R <= Voltage is equal to the divided current * the resistance, R. = 5R^2 / (3.96 + 4R) <= Simplification. I'm not quite sure where I'm going wrong. I have a funny feeling it might have something to do with voltage divider theory but I can't see how that would be incorporated. ANy help would be much appreciated.