Voltage across R, L and C vs AC Voltage source in RLC Series Circuit

Click For Summary
SUMMARY

The discussion centers on the phenomenon of voltage across resistors (R), inductors (L), and capacitors (C) in a series resonance circuit, where these voltages can exceed the source voltage. This counterintuitive behavior is explained through vector analogy, highlighting that in AC circuits, the voltage can be larger than the source due to resonant excitation. The conversation emphasizes the distinction from DC circuits, where the sum of voltages equals the source voltage, and references Faraday's Law to clarify the nature of electromotive force (EMF) in inductors.

PREREQUISITES
  • Understanding of series resonance circuits
  • Familiarity with AC and DC circuit principles
  • Knowledge of Faraday's Law and Maxwell's equations
  • Basic concepts of electromotive force (EMF) in inductors
NEXT STEPS
  • Research series resonance circuit behavior in AC analysis
  • Study the implications of Faraday's Law in electromagnetic fields
  • Explore the concept of EMF in inductors and its applications
  • Learn about vector analysis in electrical engineering contexts
USEFUL FOR

Electrical engineering students, circuit designers, and professionals interested in the behavior of RLC circuits and resonant phenomena in AC systems.

Zahid Iftikhar
Messages
121
Reaction score
24
One property of series resonance circuit is that at resonance, the voltage across circuit elements R,L and C may be larger than the source voltage. I can relate it to vector analogy where component vectors may have larger values than the resultant and the phenomenon is counter-intuitive. This does not happen in DC circuits where sum of voltage across circuit components is always equal to the source voltage. Any useful intuitive explanation of this effect please?
Characteristics of RLC Series Circuit.PNG
 
Physics news on Phys.org
A useful analogy for resonant excitation is to think about a swinging weight on the end of a rope, and you pushing it at the extreme of each swing with a small force and displacement with your fingertip.

As long as the losses are low for the swinging weight, it takes very small repetitive/resonant forces and small pushes from your fingertip to make it build up a large swing displacement -- much larger than the small periodic push amplitude of your fingertip...
 
  • Like
Likes Zahid Iftikhar and Dale
It's simply sloppy! Don't use such sloppy books! There's no voltage across an inductance, it's an EMF. In time-varying magnetic fields, there's no potential for the elctric field due to Faraday's Law, which is one of the fundamental Maxwell equations,
$$\vec{\nabla} \times \vec{E}=-\frac{1}{c} \partial_t \vec{B}.$$
 
  • Like
Likes Zahid Iftikhar
vanhees71 said:
It's simply sloppy! Don't use such sloppy books! There's no voltage across an inductance, it's an EMF. In time-varying magnetic fields, there's no potential for the elctric field due to Faraday's Law, which is one of the fundamental Maxwell equations,
$$\vec{\nabla} \times \vec{E}=-\frac{1}{c} \partial_t \vec{B}.$$
Thanks. I need more help on this please.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 21 ·
Replies
21
Views
1K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K