Voltage Calculations for Simple Circuit with Switches - VA and VB

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Discussion Overview

The discussion revolves around calculating the voltages VA and VB in a simple circuit with switches under different configurations (open and closed). The focus is on understanding the implications of circuit connectivity on voltage readings, with references to basic circuit laws and principles.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant states that when both switches are open, there is no circuit, leading to VA = 0 V and VB = 0 V.
  • Another participant challenges this by suggesting that even without a complete circuit, a voltmeter connected across the terminals could register a voltage, prompting further exploration of what voltage would be observed.
  • A third participant emphasizes that a voltage can exist independently of a circuit being complete, using the example of a disconnected battery still producing a voltage.
  • There are calculations presented for different configurations of the switches, including total resistance and voltage distribution across the circuit components.

Areas of Agreement / Disagreement

Participants generally agree that the presence of a circuit is necessary for current flow, but there is disagreement regarding the implications for voltage readings when the switches are open. The discussion remains unresolved regarding the exact voltage readings in these scenarios.

Contextual Notes

Participants have not fully explored the implications of connecting measuring devices in open circuits, and there are assumptions regarding the behavior of voltage sources that may not be universally accepted.

ƒ(x)
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Homework Statement


I'm going to try drawing the circuit. Numbers are added to it for reference. I apologize for the formatting. I'm not sure how to do white space. Edit: for VB the + is on top.

VA and VB are switches.

I need to figure out the voltage across VA and VBB when they are:
1. open, open
2. open, closed
3. closed, open
4. closed, closed

1-------(+ VA -)-------(+ 8 V -)-------2--------------3
|_______________________________|___________|
12Ω____________________________15Ω_______(+ VB -)
|_______________________________|___________|
6-----------------------------------------5--------------4

Homework Equations


V = IR
Kirchhoff's Laws

The Attempt at a Solution



1. When they are both open there isn't a circuit. So, VA = 0 V and VB = 0 V.
2. Again, no circuit.
3. There is a circuit. It has a total resistance of 27 Ω (I don't know if this matters). VA = -8 V and VB = 0 V.
4. I'm not sure about this one. There are two loops, but loop 1256 has a total resistance of 27 Ω and loop 1346 has a total resistance of 12 Ω. So 1256 gets 27/39 = 9/13 of the current and voltage and 1346 gets 12/39 = 4/13 of the current and voltage? So VA = -8*9/13 V and VB = -8*4/13 V?
 
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ƒ(x) said:
1. When they are both open there isn't a circuit. So, VA = 0 V and VB = 0 V.
Circuit or no circuit, does not give the answer. If a voltmeter (or any device) were to be connected between the 2 terminals of the switch in question, would that form a path for current to flow through the meter? If so, what voltage would it register? That's the question you must address.
 
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1. When they are both open there isn't a circuit. So, VA = 0 V and VB = 0 V.

You need a circuit for current to flow. You don't need a circuit for a voltage to be present. For example a 9V battery still produces 9V even when it's disconnected from the circuit.
 

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