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So the voltage drops across closed circuits I get that is P = V^2/R to get the power and then you will use P=I^2/R to get the current running through the circuit and in the case the current flowing through the closed circuit is equal in every resistor and so is the voltage drop. The part that I don't get is how come the voltage drop in an open circuit would change in every resistor? and is the current changing in every resistor as well?
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