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rms5643

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## Homework Statement

Find the voltage drop (V0) across the 3 kΩ resistor

Circuit Pic: http://i.imgur.com/kX7hlQK.png

CS1= 14mA

CS2= 27mA

R1 = 7kΩ

R2 = 7kΩ

R3 = 3kΩ

## Homework Equations

Ohms Law & Current Division

## The Attempt at a Solution

1) First thing I did was combine the two current sources. Since they are pointing in opposite directions, 27mA -14mA = 13mA (I'll label this as CSE)

2) Next, I tried to find the current going through R2 & R3, the resistors in series, using current division by solving: R1/(R1+(R2+R3))*(CSE) -> 7000/(7000+(3000+7000))*0.013 = 5.3mA

3) Now that I know the current through R2 & R3, I used Ohms Law to find the voltage drop across R3, the resistor in question. V0=0.0053mA*3000=16.0588V, which is incorrect.

Note: The hint in this problem says to use voltage division after combing appropriate sources and resistors, but voltage division can only be used with elements in series, not parallel, right?

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