1. The problem statement, all variables and given/known data Find the voltage drop (V0) across the 3 kΩ resistor Circuit Pic: http://i.imgur.com/kX7hlQK.png CS1= 14mA CS2= 27mA R1 = 7kΩ R2 = 7kΩ R3 = 3kΩ 2. Relevant equations Ohms Law & Current Division 3. The attempt at a solution 1) First thing I did was combine the two current sources. Since they are pointing in opposite directions, 27mA -14mA = 13mA (I'll label this as CSE) 2) Next, I tried to find the current going through R2 & R3, the resistors in series, using current division by solving: R1/(R1+(R2+R3))*(CSE) -> 7000/(7000+(3000+7000))*0.013 = 5.3mA 3) Now that I know the current through R2 & R3, I used Ohms Law to find the voltage drop across R3, the resistor in question. V0=0.0053mA*3000=16.0588V, which is incorrect. Note: The hint in this problem says to use voltage division after combing appropriate sources and resistors, but voltage division can only be used with elements in series, not parallel, right?