Voltage Required for 10A Through 6 Ohm Light Bulb

  • Thread starter Thread starter jimmy_neutron
  • Start date Start date
  • Tags Tags
    Voltage
AI Thread Summary
To support 10A of current through a 6 Ohm light bulb, a battery must provide 60V, calculated using the formula V = R x I. When adding a second light bulb in series with the original, the brightness of the first bulb will decrease due to the shared voltage from the single battery. The overall resistance increases with the additional bulb, leading to reduced current through each bulb. Participants in the discussion confirm the calculations and reasoning are correct. Understanding these principles is essential for effective circuit design.
jimmy_neutron
Messages
10
Reaction score
0
My question is this: what voltage must a battery have to support 10A of current trhough a light bulb with resistance 6 Ohms.

Is the answer simply found by: V = R x I ---- V = 6 x 10 = 60V

I believe this is correct.

Part II of my question is if you kept the same battery, but added a second light bulb in series, would the original bulb's brightness increase, decrease, or stay the same.
I believethat the original bulbs brightness would decrease because there is still only one source of energy, the battery, powering 2 light bulbs.

Can someone tell me if I am on the right track. Thank you so much!
 
Physics news on Phys.org
Yes, you are correct.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Why do the headlights on the car become dim when the car is starting?
Replies
4
Views
2K
Incandescent Bulb - suitable approximation for voltage-current curve
Replies
2
Views
898
Current, voltage : brightness of bulb in parallel or series
Replies
2
Views
4K
Comparing the brightness of each bulb in a circuit
Replies
6
Views
2K
How to find the power consumed by the light bulb
Replies
19
Views
3K
Differences in the Brightness of bulbs for 2 separate circuits
Replies
1
Views
2K
Voltage & Current & Push & Force & Potential
Replies
5
Views
2K
Does Polarity and Current Direction Affect Energy Flow in AC Circuits?
Replies
2
Views
1K
How Much Power Does a Light Bulb Use in a Series Circuit?
Replies
17
Views
2K
Brightness of bulbs depending on their watt level
Replies
11
Views
2K

Hot Threads

Recent Insights

Back
Top