What Caused the Lower Resistance in the Second Graph?

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SUMMARY

The discussion centers on the observed lower resistance in a p-doped germanium (Ge) sample when subjected to a magnetic field, specifically at B = 0. The participant hypothesizes that the accumulation of positive charges leads to a lower voltage and resistance. Concerns are raised regarding the large error bars in the measurements and the impact of temperature on resistance readings. The participant confirms that temperature was controlled, but the error bars are attributed to instrument limitations.

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MementoMori96
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Hi, in laboratory i had a sample of Ge with p-doping. In a first place i have done different measure V vs I (first image)

Then i insert the sample in a magnetic field perpendicular to the sample.

And i have done measure of V vs B (with a fixed current at 8 mA) and i obtained the second image.

As you can see at B = 0 the R is lower than the resistance of the first graph. Why ?

I suppose this third image

The is an accumolation of positive charges at right and so we measure a lower Voltage with a lower resistance

Can be this correct?
 

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MementoMori96 said:
As you can see at B = 0 the R is lower than the resistance of the first graph. Why ?
It looks like the top of your error bar at B=0 is close to what you measured in the first test. Why are the error bars so large?

Also, temperature will affect the "resistance" reading. How did you control for temperature?
 
Yes is close but with a Z test alpha 5% the two values are not compatible. The error bars are large due to the instruments. The temperature is the same.

What do you think about my idea?
 

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