Volume Change by Pressure: How Does Pressure Affect the Volume of an Object?

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SUMMARY

The discussion focuses on calculating the volume change of a gold coin with a mass of 25 kg at a depth of 5000 meters, where the pressure is approximately 50.3604 MPa. Participants emphasize the need to apply Boyle's Law for volume calculations and Charles's Law for temperature adjustments, while also noting the importance of the bulk modulus and coefficients for thermal expansion. The coefficient of volume expansion is highlighted as being three times higher than the linear thermal expansion coefficient. Key resources for further understanding include links to bulk modulus definitions and thermal expansion coefficients.

PREREQUISITES
  • Understanding of Boyle's Law and Charles's Law
  • Knowledge of bulk modulus and its application
  • Familiarity with thermal expansion coefficients
  • Basic principles of solid mechanics
NEXT STEPS
  • Research "Bulk compressibility" and its implications for volume change
  • Study "Volumetric thermal expansion" and its calculations
  • Learn how to apply the bulk modulus formula for solids
  • Investigate temperature profiles of ocean water at various depths
USEFUL FOR

Students in physics or engineering, particularly those studying fluid mechanics, solid mechanics, and thermal dynamics, as well as professionals involved in material science and underwater engineering.

robax25
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Homework Statement


It is necessary to calculate the volume of the coin which has mass 25 kg and how does change its volume when it is necessary to calculate its volume at a depth of 5000m. Compare volume change by pressure with the volume change by pressure with the Volume change by temperature.

Homework Equations


volume at surface, M=25kg ρ=m/v
v=1.294 * 10^-3 m³ density of gold ρ= 19320 kg/m³

The Attempt at a Solution



v=1.294 * 10^-3 m³[/B]
I do not know how to calculate the volume at a depth of 5000m but I have pressure at a depth of 5000m.It is 50.3604 MPA. Now I need to find out Temperature using Pressure.
 
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You are not told the temperature? Then how are you supposed to determine it?
 
Actually I need the volume at a water depth of 5000m . I can use Boyle's law to calculate Volume and charl's law to calculate Temperatur
 
I do not how to proceed
 
robax25 said:
Actually I need the volume at a water depth of 5000m . I can use Boyle's law to calculate Volume and charl's law to calculate Temperatur
You are dealing with a solid, not a gas.

Do you know the equation for the volume change of a solid as a function of the temperature change and the pressure change?
 
Sorry, I don't know
 
robax25 said:
Sorry, I don't know
Do you have a textbook? Otherwise, Google "Bulk compressibility" and "Volumetric thermal expansion."
 
L=αLT however, I do not know the temperature
 
  • #10
robax25 said:
L=αLT however, I do not know the temperature
That's the coefficient of linear thermal expansion. The coefficient of volume expansion is 3 x as high.

I guess you need to look up the temperature of the ocean at a depth of 5000 m.
 
  • #11
I get it 3 degree Celsius
 
  • #12
Sorry, I learned this formula in structural Mechanics course but I forget it.
 
  • #13
here I know only volume and how to proceed?
 
  • #14
how can I calculate the volume at a water depth 5000m?
 
  • #15
sorry, I get it but How to calculate volume change by pressure?
 
  • #16
robax25 said:
sorry, I get it but How to calculate volume change by pressure?
https://en.m.wikipedia.org/wiki/Bulk_modulus
Note, however, that there it quite correctly defines it as response to a small change in pressure. This is because, in principle, the modulus depends on the pressure, so what works for a small change won't work for a large one. But I think you'll have to overlook that subtlety.
 

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