Volume expansion problem wheres initial volume?

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SUMMARY

The discussion centers on calculating the coefficient of volume expansion (beta) for a liquid with a maximum density of 0.6 g/cm³ at 3.7°C and a density of 0.60888 g/cm³ at 11.4°C. The formula used is beta = deltaV / (initial volume * delta temperature), where the initial volume is assumed to be 1 cm³. The incorrect calculation of beta as 0.00115325 indicates a misunderstanding of the relationship between density changes and volume expansion. The correct approach requires a more precise calculation of deltaV based on the change in density over the specified temperature interval.

PREREQUISITES
  • Understanding of the concepts of density and volume expansion
  • Familiarity with the formula for calculating volume expansion (deltaV = beta * initial volume * delta temperature)
  • Basic knowledge of temperature scales (Celsius and Kelvin)
  • Ability to perform calculations involving changes in physical properties of liquids
NEXT STEPS
  • Calculate the change in volume using the correct densities at the specified temperatures
  • Learn about the relationship between density and volume expansion in liquids
  • Explore the concept of thermal expansion coefficients for various substances
  • Review the principles of thermodynamics related to liquid states and phase changes
USEFUL FOR

Students in physics or chemistry, educators teaching thermodynamics, and professionals involved in material science or fluid dynamics will benefit from this discussion.

Dantes
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A liquid has a maximum density of 0.6 g/cm^3 at 3.7 C. At 11.4C , its density is 0.60888 g/cm^3. What is beta for this liquid over this temperature interval? Answer in units of (C)^-1.

Obviously this has to do with the volume expansion so I made the formula deltaV = beta * initial volume * delta temperature into beta = deltaV / (initial volume * delta temperature) assuming that initial volume is 1 cm since its not stated in the problem and that's wrong.

I came out with 0.00115325 doing it that way. System says I am wrong.

Am I on the right track or am I not thinking outside the box enough?
 
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Hmm...switching to kelvin opps :biggrin:

edit: doesn't matter since its a constant.
 
Dantes said:
A liquid has a maximum density of 0.6 g/cm^3 at 3.7 C. At 11.4C , its density is 0.60888 g/cm^3. What is beta for this liquid over this temperature interval? Answer in units of (C)^-1.
Obviously this has to do with the volume expansion so I made the formula deltaV = beta * initial volume * delta temperature into beta = deltaV / (initial volume * delta temperature) assuming that initial volume is 1 cm since its not stated in the problem and that's wrong.
I came out with 0.00115325 doing it that way. System says I am wrong.
Am I on the right track or am I not thinking outside the box enough?

Is 0.60888 less than, equal to, or greater than 0.6? Methinks you need to check the question, and if you've copied it correctly, it's time to pick bones with whoever programs the exercises into the "system."
 

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