Volume of a shape with a different trapezium at each end

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SUMMARY

The discussion focuses on calculating the volume of a prism-shaped solid with two trapeziums at each end, specifically Trapezium 1 with dimensions a = 65.5m, b = 35.5m, h = 3.5m, and Trapezium 2 with a = 53m, b = 17.5m, h = 3m, positioned 48m apart. The solution involves determining the cross-sectional area A(x) at a distance x from one end, using proportions to express the top, bottom, and height of the trapezoids. The final volume is computed using the integral formula ∫_0^{48} A(x) dx.

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1. Volume of a shape with a different trapezium at each end.
Trapezium 1: a(top side) = 65.5m, b = 35.5m, h = 3.5m, height above sea level = 3m. Trapezium 2: a = 53m, b = 17.5m, h = 3m, HASL = 1.6m. Trapezoids are parallel and 48m apart. Their horizontal centres are aligned (as in sections of a reservoir).




2. Need an equation



3. Need a solution!
 
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I assume the similar corners of the two trapezoids are connected by straight lines and you want the volume of the prism shaped solid that encloses. Consider a plane parallel to the ends at a distance x from one of the ends, giving a cross section area A(x). You should be able to figure the top, bottom and height of that cross section in terms of x using proportions. Once you have its area A(x) in terms of x, the volume would be

[tex]\int_0^{48} A(x)\,dx[/tex]
 

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