Volume of a solid limited by two paraboloids

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The discussion centers on calculating the volume of a solid bounded by the paraboloids z=2x^2+y^2 and z=12-x^2-2y^2. One user claims to have found the volume to be 24π and seeks confirmation and a step-by-step solution. Participants suggest finding the intersection of the two functions and integrating the difference over the relevant area. There is a note that the thread should have been posted in the Calculus & Beyond section instead of Precalculus Math. The user expresses relief upon receiving positive feedback about their initial calculation.
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Volume of a solid limited by these two paraboloids z=2x^2{}+y^2{} and z=12-x^2{}-2y^2{}



hi can someone help me? I tried to solve this and my solution was \ 24\Pi is it correct? can someone solve this step by step?
 
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I am assuming you are in calculus. In this case you would find the intersection of these two functions, and integrate the difference of the two functions over the areas.
 
aicort said:
Volume of a solid limited by these two paraboloids z=2x^2{}+y^2{} and z=12-x^2{}-2y^2{}



hi can someone help me? I tried to solve this and my solution was \ 24\Pi is it correct? can someone solve this step by step?

How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.
 
Mark44 said:
How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.

yeah i know... i realized too late :P i hope someone move this thread to that section
look this is what i did

http://img413.imageshack.us/img413/2806/volt.th.jpg
 
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Looks good to me
 
you say so? I'm glad then... i thought it was wrong
thanks you guys :)
 

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