(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the volume of the solid that results when the region bounded by the curves y=16-x[tex]^{2}[/tex] and y=16-4x is revolved around x=8.

If you could show me how to do it with both the shell method and washer method it would be greatly appreciated.

2. Relevant equations

3. The attempt at a solution

When trying the shell method i tried to shift the graph to the left 8 units and then revolving it about the y axis and got:

y=16-(x+8)[tex]^{2}[/tex] and y = 16-4(x+8) which gave me

2[tex]\pi[/tex]*[tex]\int^{-4}_{-8}[/tex]x(16-(x+8)[tex]^{2}[/tex] - (16-4(x+8))) dx

and that gave me a negative answer so I know that can't be right

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# Homework Help: Volume of a solid of revolution

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